trolls2 hw8 item5

Answers

PART A: @DIV{(μ@Sub{0}I@Sub{1}I@Sub{2}a@Sup{2});2π(d@Sup{2}-@DIV{a@Sup{2};4})}
PART B: μ@Sub{0}I@Sub{2}@DIV{m;2π(d@Sup{2}-@DIV{a@Sup{2};4})}
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